3.1.23 \(\int (d+c^2 d x^2)^3 (a+b \sinh ^{-1}(c x)) \, dx\) [23]

Optimal. Leaf size=170 \[ -\frac {16 b d^3 \sqrt {1+c^2 x^2}}{35 c}-\frac {8 b d^3 \left (1+c^2 x^2\right )^{3/2}}{105 c}-\frac {6 b d^3 \left (1+c^2 x^2\right )^{5/2}}{175 c}-\frac {b d^3 \left (1+c^2 x^2\right )^{7/2}}{49 c}+d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right ) \]

[Out]

-8/105*b*d^3*(c^2*x^2+1)^(3/2)/c-6/175*b*d^3*(c^2*x^2+1)^(5/2)/c-1/49*b*d^3*(c^2*x^2+1)^(7/2)/c+d^3*x*(a+b*arc
sinh(c*x))+c^2*d^3*x^3*(a+b*arcsinh(c*x))+3/5*c^4*d^3*x^5*(a+b*arcsinh(c*x))+1/7*c^6*d^3*x^7*(a+b*arcsinh(c*x)
)-16/35*b*d^3*(c^2*x^2+1)^(1/2)/c

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Rubi [A]
time = 0.11, antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {200, 5784, 12, 1813, 1864} \begin {gather*} \frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+d^3 x \left (a+b \sinh ^{-1}(c x)\right )-\frac {b d^3 \left (c^2 x^2+1\right )^{7/2}}{49 c}-\frac {6 b d^3 \left (c^2 x^2+1\right )^{5/2}}{175 c}-\frac {8 b d^3 \left (c^2 x^2+1\right )^{3/2}}{105 c}-\frac {16 b d^3 \sqrt {c^2 x^2+1}}{35 c} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + c^2*d*x^2)^3*(a + b*ArcSinh[c*x]),x]

[Out]

(-16*b*d^3*Sqrt[1 + c^2*x^2])/(35*c) - (8*b*d^3*(1 + c^2*x^2)^(3/2))/(105*c) - (6*b*d^3*(1 + c^2*x^2)^(5/2))/(
175*c) - (b*d^3*(1 + c^2*x^2)^(7/2))/(49*c) + d^3*x*(a + b*ArcSinh[c*x]) + c^2*d^3*x^3*(a + b*ArcSinh[c*x]) +
(3*c^4*d^3*x^5*(a + b*ArcSinh[c*x]))/5 + (c^6*d^3*x^7*(a + b*ArcSinh[c*x]))/7

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 200

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[ExpandIntegrand[(a + b*x^n)^p, x], x] /; FreeQ[{a, b}, x]
&& IGtQ[n, 0] && IGtQ[p, 0]

Rule 1813

Int[(Pq_)*(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[x^((m - 1)/2)*SubstFor[x^2,
Pq, x]*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, p}, x] && PolyQ[Pq, x^2] && IntegerQ[(m - 1)/2]

Rule 1864

Int[(Pq_)*((a_) + (b_.)*(x_)^(n_.))^(p_.), x_Symbol] :> Int[ExpandIntegrand[Pq*(a + b*x^n)^p, x], x] /; FreeQ[
{a, b, n}, x] && PolyQ[Pq, x] && (IGtQ[p, 0] || EqQ[n, 1])

Rule 5784

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u = IntHide[(d + e*x^2
)^p, x]}, Dist[a + b*ArcSinh[c*x], u, x] - Dist[b*c, Int[SimplifyIntegrand[u/Sqrt[1 + c^2*x^2], x], x], x]] /;
FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int \left (d+c^2 d x^2\right )^3 \left (a+b \sinh ^{-1}(c x)\right ) \, dx &=d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )-(b c) \int \frac {d^3 x \left (35+35 c^2 x^2+21 c^4 x^4+5 c^6 x^6\right )}{35 \sqrt {1+c^2 x^2}} \, dx\\ &=d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{35} \left (b c d^3\right ) \int \frac {x \left (35+35 c^2 x^2+21 c^4 x^4+5 c^6 x^6\right )}{\sqrt {1+c^2 x^2}} \, dx\\ &=d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{70} \left (b c d^3\right ) \text {Subst}\left (\int \frac {35+35 c^2 x+21 c^4 x^2+5 c^6 x^3}{\sqrt {1+c^2 x}} \, dx,x,x^2\right )\\ &=d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{70} \left (b c d^3\right ) \text {Subst}\left (\int \left (\frac {16}{\sqrt {1+c^2 x}}+8 \sqrt {1+c^2 x}+6 \left (1+c^2 x\right )^{3/2}+5 \left (1+c^2 x\right )^{5/2}\right ) \, dx,x,x^2\right )\\ &=-\frac {16 b d^3 \sqrt {1+c^2 x^2}}{35 c}-\frac {8 b d^3 \left (1+c^2 x^2\right )^{3/2}}{105 c}-\frac {6 b d^3 \left (1+c^2 x^2\right )^{5/2}}{175 c}-\frac {b d^3 \left (1+c^2 x^2\right )^{7/2}}{49 c}+d^3 x \left (a+b \sinh ^{-1}(c x)\right )+c^2 d^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{5} c^4 d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{7} c^6 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )\\ \end {align*}

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Mathematica [A]
time = 0.07, size = 119, normalized size = 0.70 \begin {gather*} \frac {d^3 \left (105 a c x \left (35+35 c^2 x^2+21 c^4 x^4+5 c^6 x^6\right )-b \sqrt {1+c^2 x^2} \left (2161+757 c^2 x^2+351 c^4 x^4+75 c^6 x^6\right )+105 b c x \left (35+35 c^2 x^2+21 c^4 x^4+5 c^6 x^6\right ) \sinh ^{-1}(c x)\right )}{3675 c} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + c^2*d*x^2)^3*(a + b*ArcSinh[c*x]),x]

[Out]

(d^3*(105*a*c*x*(35 + 35*c^2*x^2 + 21*c^4*x^4 + 5*c^6*x^6) - b*Sqrt[1 + c^2*x^2]*(2161 + 757*c^2*x^2 + 351*c^4
*x^4 + 75*c^6*x^6) + 105*b*c*x*(35 + 35*c^2*x^2 + 21*c^4*x^4 + 5*c^6*x^6)*ArcSinh[c*x]))/(3675*c)

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Maple [A]
time = 0.52, size = 156, normalized size = 0.92

method	result	size
derivativedivides	\(\frac {d^{3} a \left (\frac {1}{7} c^{7} x^{7}+\frac {3}{5} c^{5} x^{5}+c^{3} x^{3}+c x \right )+d^{3} b \left (\frac {\arcsinh \left (c x \right ) c^{7} x^{7}}{7}+\frac {3 \arcsinh \left (c x \right ) c^{5} x^{5}}{5}+\arcsinh \left (c x \right ) c^{3} x^{3}+\arcsinh \left (c x \right ) c x -\frac {c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{49}-\frac {117 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{1225}-\frac {757 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{3675}-\frac {2161 \sqrt {c^{2} x^{2}+1}}{3675}\right )}{c}\)	\(156\)
default	\(\frac {d^{3} a \left (\frac {1}{7} c^{7} x^{7}+\frac {3}{5} c^{5} x^{5}+c^{3} x^{3}+c x \right )+d^{3} b \left (\frac {\arcsinh \left (c x \right ) c^{7} x^{7}}{7}+\frac {3 \arcsinh \left (c x \right ) c^{5} x^{5}}{5}+\arcsinh \left (c x \right ) c^{3} x^{3}+\arcsinh \left (c x \right ) c x -\frac {c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{49}-\frac {117 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{1225}-\frac {757 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{3675}-\frac {2161 \sqrt {c^{2} x^{2}+1}}{3675}\right )}{c}\)	\(156\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x,method=_RETURNVERBOSE)

[Out]

1/c*(d^3*a*(1/7*c^7*x^7+3/5*c^5*x^5+c^3*x^3+c*x)+d^3*b*(1/7*arcsinh(c*x)*c^7*x^7+3/5*arcsinh(c*x)*c^5*x^5+arcs
inh(c*x)*c^3*x^3+arcsinh(c*x)*c*x-1/49*c^6*x^6*(c^2*x^2+1)^(1/2)-117/1225*c^4*x^4*(c^2*x^2+1)^(1/2)-757/3675*c
^2*x^2*(c^2*x^2+1)^(1/2)-2161/3675*(c^2*x^2+1)^(1/2)))

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 301 vs. \(2 (150) = 300\).
time = 0.27, size = 301, normalized size = 1.77 \begin {gather*} \frac {1}{7} \, a c^{6} d^{3} x^{7} + \frac {3}{5} \, a c^{4} d^{3} x^{5} + \frac {1}{245} \, {\left (35 \, x^{7} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {5 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{2}} - \frac {6 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{6}} - \frac {16 \, \sqrt {c^{2} x^{2} + 1}}{c^{8}}\right )} c\right )} b c^{6} d^{3} + \frac {1}{25} \, {\left (15 \, x^{5} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {3 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{2}} - \frac {4 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1}}{c^{6}}\right )} c\right )} b c^{4} d^{3} + a c^{2} d^{3} x^{3} + \frac {1}{3} \, {\left (3 \, x^{3} \operatorname {arsinh}\left (c x\right ) - c {\left (\frac {\sqrt {c^{2} x^{2} + 1} x^{2}}{c^{2}} - \frac {2 \, \sqrt {c^{2} x^{2} + 1}}{c^{4}}\right )}\right )} b c^{2} d^{3} + a d^{3} x + \frac {{\left (c x \operatorname {arsinh}\left (c x\right ) - \sqrt {c^{2} x^{2} + 1}\right )} b d^{3}}{c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="maxima")

[Out]

1/7*a*c^6*d^3*x^7 + 3/5*a*c^4*d^3*x^5 + 1/245*(35*x^7*arcsinh(c*x) - (5*sqrt(c^2*x^2 + 1)*x^6/c^2 - 6*sqrt(c^2
*x^2 + 1)*x^4/c^4 + 8*sqrt(c^2*x^2 + 1)*x^2/c^6 - 16*sqrt(c^2*x^2 + 1)/c^8)*c)*b*c^6*d^3 + 1/25*(15*x^5*arcsin
h(c*x) - (3*sqrt(c^2*x^2 + 1)*x^4/c^2 - 4*sqrt(c^2*x^2 + 1)*x^2/c^4 + 8*sqrt(c^2*x^2 + 1)/c^6)*c)*b*c^4*d^3 +
a*c^2*d^3*x^3 + 1/3*(3*x^3*arcsinh(c*x) - c*(sqrt(c^2*x^2 + 1)*x^2/c^2 - 2*sqrt(c^2*x^2 + 1)/c^4))*b*c^2*d^3 +
a*d^3*x + (c*x*arcsinh(c*x) - sqrt(c^2*x^2 + 1))*b*d^3/c

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Fricas [A]
time = 0.34, size = 169, normalized size = 0.99 \begin {gather*} \frac {525 \, a c^{7} d^{3} x^{7} + 2205 \, a c^{5} d^{3} x^{5} + 3675 \, a c^{3} d^{3} x^{3} + 3675 \, a c d^{3} x + 105 \, {\left (5 \, b c^{7} d^{3} x^{7} + 21 \, b c^{5} d^{3} x^{5} + 35 \, b c^{3} d^{3} x^{3} + 35 \, b c d^{3} x\right )} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) - {\left (75 \, b c^{6} d^{3} x^{6} + 351 \, b c^{4} d^{3} x^{4} + 757 \, b c^{2} d^{3} x^{2} + 2161 \, b d^{3}\right )} \sqrt {c^{2} x^{2} + 1}}{3675 \, c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="fricas")

[Out]

1/3675*(525*a*c^7*d^3*x^7 + 2205*a*c^5*d^3*x^5 + 3675*a*c^3*d^3*x^3 + 3675*a*c*d^3*x + 105*(5*b*c^7*d^3*x^7 +
21*b*c^5*d^3*x^5 + 35*b*c^3*d^3*x^3 + 35*b*c*d^3*x)*log(c*x + sqrt(c^2*x^2 + 1)) - (75*b*c^6*d^3*x^6 + 351*b*c
^4*d^3*x^4 + 757*b*c^2*d^3*x^2 + 2161*b*d^3)*sqrt(c^2*x^2 + 1))/c

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Sympy [A]
time = 0.73, size = 221, normalized size = 1.30 \begin {gather*} \begin {cases} \frac {a c^{6} d^{3} x^{7}}{7} + \frac {3 a c^{4} d^{3} x^{5}}{5} + a c^{2} d^{3} x^{3} + a d^{3} x + \frac {b c^{6} d^{3} x^{7} \operatorname {asinh}{\left (c x \right )}}{7} - \frac {b c^{5} d^{3} x^{6} \sqrt {c^{2} x^{2} + 1}}{49} + \frac {3 b c^{4} d^{3} x^{5} \operatorname {asinh}{\left (c x \right )}}{5} - \frac {117 b c^{3} d^{3} x^{4} \sqrt {c^{2} x^{2} + 1}}{1225} + b c^{2} d^{3} x^{3} \operatorname {asinh}{\left (c x \right )} - \frac {757 b c d^{3} x^{2} \sqrt {c^{2} x^{2} + 1}}{3675} + b d^{3} x \operatorname {asinh}{\left (c x \right )} - \frac {2161 b d^{3} \sqrt {c^{2} x^{2} + 1}}{3675 c} & \text {for}\: c \neq 0 \\a d^{3} x & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c**2*d*x**2+d)**3*(a+b*asinh(c*x)),x)

[Out]

Piecewise((a*c**6*d**3*x**7/7 + 3*a*c**4*d**3*x**5/5 + a*c**2*d**3*x**3 + a*d**3*x + b*c**6*d**3*x**7*asinh(c*
x)/7 - b*c**5*d**3*x**6*sqrt(c**2*x**2 + 1)/49 + 3*b*c**4*d**3*x**5*asinh(c*x)/5 - 117*b*c**3*d**3*x**4*sqrt(c
**2*x**2 + 1)/1225 + b*c**2*d**3*x**3*asinh(c*x) - 757*b*c*d**3*x**2*sqrt(c**2*x**2 + 1)/3675 + b*d**3*x*asinh
(c*x) - 2161*b*d**3*sqrt(c**2*x**2 + 1)/(3675*c), Ne(c, 0)), (a*d**3*x, True))

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (d\,c^2\,x^2+d\right )}^3 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*asinh(c*x))*(d + c^2*d*x^2)^3,x)

[Out]

int((a + b*asinh(c*x))*(d + c^2*d*x^2)^3, x)

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